Static linear response: theory: Difference between revisions

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Let’s consider three types of static perturbations
Let’s consider three types of static perturbations
# atomic displacements <math display="inline">u_m</math>  
# atomic displacements <math display="inline">u_m</math> with <math>m=I\alpha</math> with <math>I=\{1..N_\text{atoms}\}</math> and <math>\alpha=\{1..3\}</math>
# homogeneous strains <math display="inline">\eta_j</math> with <math display="inline">j=\{1..6\}</math>  
# homogeneous strains <math display="inline">\eta_j</math> with <math display="inline">j=\{1..6\}</math>  
# static electric field <math display="inline">\mathcal{E}_\alpha</math> with <math display="inline">\alpha=\{1..3\}</math>
# static electric field <math display="inline">\mathcal{E}_\alpha</math> with <math display="inline">\alpha=\{1..3\}</math>


By performing a Taylor expansion of the total energy in terms of these perturbations we obtain
By performing a Taylor expansion of the total energy in terms of these perturbations we obtain{{cite|wu:prb:2005}}
:<math>
:<math>
\begin{aligned}
\begin{aligned}
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\qquad \text{force response internal strain tensor}
\qquad \text{force response internal strain tensor}
</math>
</math>
== References ==

Revision as of 15:00, 1 August 2022

Let’s consider three types of static perturbations

  1. atomic displacements with with and
  2. homogeneous strains with
  3. static electric field with

By performing a Taylor expansion of the total energy in terms of these perturbations we obtain[1]


The derivatives of the energy with respect to an electric field are the polarization, with respect to atomic displacements are the forces, with respect to changes in the lattice vectors are the stress tensor.

This leads to the following ‘clamped-ion’ or ‘frozen-ion’ definitions:

References